3/64=96(1/2)^n-1

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Solution for 3/64=96(1/2)^n-1 equation: 



3/64=96(1/2)^n-1

We move all terms to the left:

3/64-(96(1/2)^n-1)=0



Domain of the equation: 2)^n-1)!=0

n!=0/1

n!=0

n∈R



We add all the numbers together, and all the variables

-(96(+1/2)^n-1)+3/64=0

We calculate fractions


()/2^n-1)*64)+6n/2^n-1)*64)=0

We calculate fractions


(()*2^n)/4n^2+(-1)*64)+6n*2^n)/4n^2=0

We multiply all the terms by the denominator


(()*2^n)+(-1)*64)+6n*2^n)=0



We calculate terms in parentheses: +(()*2^n), so:

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We get rid of parentheses

(()*2^n)-1)*64)+6n*2^n=0



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